At start you have 1/3 chance if you randomly pick a door.
When you remove 1 door, you have 1/2 which is better.
But I’m with you, it’s bizarre that it works 🤷🏼♀️!
Edit: For the non math curious downvoters: it is exactly how it works, you start out with a 1/3 choice (~33% win chance). If you randomly chose again after the door opening (the door conceniently being empty) you have 1/2, which is … Better. So it is better to change. You can try it out with 10 or a houndred doors, the result is actually the same, you just get stuck on the “forced” change of doors because there are so few to chose from.
I didn’t provide the exact numbers, but stated that because the odds are now better for a random selection, is the reason for switching. Am I that bad at explaining 😭
At start you have 1/3 chance if you randomly pick a door.
When you remove 1 door, you have 1/2 which is better.
But I’m with you, it’s bizarre that it works 🤷🏼♀️!
Edit: For the non math curious downvoters: it is exactly how it works, you start out with a 1/3 choice (~33% win chance). If you randomly chose again after the door opening (the door conceniently being empty) you have 1/2, which is … Better. So it is better to change. You can try it out with 10 or a houndred doors, the result is actually the same, you just get stuck on the “forced” change of doors because there are so few to chose from.
This is not how it works, this way you wouldn’t improve your chances by switching doors.
Well explain how it works then. Because you know, it does work.
Ok, assume you pick door number one. There’s three possibilities; the car is either behind door number one, two or three. Now:
So two out of three times, you’ve won a car by switching doors. So you have a 2/3 chance of winnin by switching, or a 1/3 chance by not switching.
Very good explanation, thanks!
I didn’t provide the exact numbers, but stated that because the odds are now better for a random selection, is the reason for switching. Am I that bad at explaining 😭